The amount of NH 4 + ions present as NH 4 NO 3 in a sample of fertilizer is to be determined. Direct titration of NH 4 + would not reveal an accurate…
The amount of NH4+ ions present as NH4NO3 in a sample of fertilizer is to be determined. Direct titration of NH4+ would not reveal an accurate result. Instead, NH4NO3 is reacted with Xs NaOH and this solution is then titrated with HCl in order to determine the amount of -OH required to neutralize all the NH4+ ions.
1.50 g of fertilizer is transferred carefully into a 100 mL volumetric flask and made up to the mark, using distilled water. Aliquots of 10 mL of this solution are then added to conical flasks that also contain 40 mL of 0.210 M NaOH.
Save your time - order a paper!
Get your paper written from scratch within the tight deadline. Our service is a reliable solution to all your troubles. Place an order on any task and we will take care of it. You won’t have to worry about the quality and deadlines
Order Paper NowThese solutions are then titrated with a standard solution of 0.26 M HCl (average titre is 28.80 cm3).
Calculate the number of moles of NH4+ ions in the 100 mL volumetric flask and the % by mass NH4NO3 in the fertilizer
. WITH nursingessayswriters.com AND GET AN AMAZING DISCOUNT!
The post The amount of NH 4 + ions present as NH 4 NO 3 in a sample of fertilizer is to be determined. Direct titration of NH 4 + would not reveal an accurate… appeared first on nursingessayswriters.com.
The amount of NH 4 + ions present as NH 4 NO 3 in a sample of fertilizer is to be determined. Direct titration of NH 4 + would not reveal an accurate… was first posted on October 25, 2020 at 10:32 pm.
©2019 "nursingessayswriters.com". Use of this feed is for personal non-commercial use only. If you are not reading this article in your feed reader, then the site is guilty of copyright infringement. Please contact me at admin@nursingessayswriters.com