Sheet1
| HOMEWORK 4 Solution |
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Internal Angles |
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A |
110 |
0 |
15 |
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B |
115 |
0 |
30 |
‘ |
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C |
110 |
0 |
10 |
‘ |
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D |
118 |
0 |
0 |
‘ |
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E |
125 |
0 |
5 |
‘ |
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F |
130 |
0 |
0 |
‘ |
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Direction |
Azimuth |
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Reverse Azimuth |
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Internal Angle |
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Azimuth of Next Direction |
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AB |
80 |
0 |
0 |
‘ |
260 |
0 |
0 |
‘ |
117 |
0 |
20 |
‘ |
144 |
0 |
30 |
‘ |
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BC |
144 |
0 |
30 |
‘ |
324 |
0 |
30 |
‘ |
112 |
0 |
0 |
‘ |
212 |
0 |
30 |
‘ |
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CD |
214 |
0 |
20 |
‘ |
34 |
0 |
20 |
‘ |
119 |
0 |
50 |
‘ |
275 |
0 |
0 |
‘ |
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DE |
276 |
0 |
20 |
‘ |
96 |
0 |
20 |
‘ |
196 |
0 |
55 |
‘ |
331 |
0 |
15 |
‘ |
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EF |
331 |
0 |
15 |
‘ |
151 |
0 |
15 |
‘ |
131 |
0 |
50 |
‘ |
20 |
0 |
-35 |
‘ |
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FA |
21 |
0 |
15 |
‘ |
201 |
0 |
15 |
‘ |
112 |
0 |
5 |
‘ |
89 |
0 |
10 |
‘ |
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Sum of Internal angles |
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709° |
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Misclosure=720-709 |
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11° |
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For 2a |
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COURSE |
AZIMUTH |
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DISTANCE |
LATITUDE |
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DEPARTURE |
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AB |
71 |
° |
11 |
‘ |
164.95 |
53.2 |
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156.13 |
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BC |
149 |
° |
0 |
‘ |
88.41 |
-75.78 |
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45.53 |
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CD |
224 |
° |
18 |
‘ |
121.69 |
-87.09 |
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-84.99 |
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DE |
291 |
° |
13 |
‘ |
115.89 |
41.94 |
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-108.03 |
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EA |
352 |
° |
39 |
‘ |
68.42 |
67.86 |
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-8.75 |
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M ISCLOSURE |
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0.13 |
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-0.11 |
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For 2b |
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ERROR OF MISCLOSURE= |
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0.17 |
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PRECISION RATIO= |
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0.17/559.36 |
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0.0000303918 |
Sheet2
| Course |
Distance |
Azimuth |
Latitudes |
Departures |
| AB |
164.95′ |
N71°11’E |
53.2 |
156.13 |
| BC |
88.41′ |
S149°00’E |
-71.78 |
45.53 |
| CD |
121.69′ |
S224°18’W |
-87.27 |
-84.81 |
| DE |
115.89′ |
N291°13’W |
54.97 |
-108.03 |
| EA |
68.42′ |
N352°39’W |
67.86 |
-8.75 |
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16.98 |
559.36 |
| Perimeter |
559.36′ |
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16.98 |
0.07 |
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Error=sqrt(16.98sqd+0.07sqd)=16.98′ |
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Traverse survey does not close |
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Precision |
0.0303561213 |
Sheet3
