In the experiment of Synthesis of Alum, we are asked in our report sheet to calculate the moles of Aluminum. In the experiment, I weighed 1.
In the experiment of Synthesis of Alum, we are asked in our report sheet to calculate the moles of Aluminum. In the experiment, I weighed 1.0611g of aluminum foil, so since I know the chemical formula of aluminum foil is Al2O3, how would I go about finding the moles of just aluminum?
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Order Paper NowIn the experiment of Synthesis of Alum, we are asked in our report sheet to calculate the moles of Aluminum. In the experiment, I weighed 1. was first posted on November 1, 2020 at 2:08 am.
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