c) A volume of 9 x 104 L of gas at 100 kPa and 20 C is placed in a pressurized container at 1.5 x 103 kPa and 0 C. ( this is my question) here is how…
pressurized container at 1.5 x 103 kPa and 0 °C. ( this is my question) here is how I have started solving it: I have a feeling I am getting it kinda wrongP1 x V1 = P2 x V2 T2 100kPa x (9×104)L = (1.5 x 103)kPa x V273K30716.72 = 5.49V30716.72 / 5.49 = 5.49V / 5.495595.03 = V
The post c) A volume of 9 x 104 L of gas at 100 kPa and 20 C is placed in a pressurized container at 1.5 x 103 kPa and 0 C.
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Order Paper Nowc) A volume of 9 x 104 L of gas at 100 kPa and 20 C is placed in a pressurized container at 1.5 x 103 kPa and 0 C. ( this is my question) here is how… was first posted on November 13, 2020 at 11:45 pm.
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