Theorem

Given a segment AB and a ray −−→CD, there is a point X on−−→CD so that AB ∼= CX.Proof. Let AB and −−→CD be given. Figure 1: Given starting point forTheorem 28Theorem 29 (Problem 18). Given two points A and B (see Figure 2, there is a thirdpoint C not on←→AB such that A, B, […]

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