Coulomb’s law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is | F |= K | QQ | d 2 , where K…
Coulomb’s law for the magnitude of the force F
between two particles with charges Q
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′
separated by a distance d
is
|F|=K|QQ
′
|
d
2
,
where K=1
4πϵ
0
, and ϵ
0
=8.854×10
−12
C
2
/(N⋅m
2
)
is the permittivity of free space.
Consider two point charges located on the x axis: one charge, q
1
= -19.0 nC
, is located at x
1
= -1.745 m
; the second charge, q
2
= 36.0 nC
, is at the origin (x=0.0000)
What is the net force exerted by these two charges on a third charge q
3
= 52.5 nC
placed between q
1
and q
2
at x
3
= -1.060 m
?
Your answer may be positive or negative, depending on the direction of the force.
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Coulomb’s law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is | F |= K | QQ | d 2 , where K… was first posted on October 25, 2020 at 5:27 pm.
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