What must be the capacitance (in pFmathrm{pF}pF ) of the circuit so that the radio is tuned to a frequency of f=6.95MHzmathrm{f}=6.95 mathrm{MHz}f=6.95MHz ?
1. Radios often utilize a variable capacitor (capacitance is changed by either changing the distance between plates or amount of dielectric between plates) in series with an inductor to tune the circuit to a particular frequency. In a particular shortwave radio, the value of the inductor is L=1.09μH.L=1.09 mu H . What must be the capacitance (in pFmathrm{pF} ) of the circuit so that the radio is tuned to a frequency of f=6.95MHzmathrm{f}=6.95 mathrm{MHz} ?
2. A conducting coil, with current i(t)=4.20∗e0.0250tsin(120πt)i(t)=4.20 * e^{0.0250 t} sin (120 pi t), with i in amperes and tt in seconds, is placed next to a second coil, end to end. At t=0.740 smathrm{t}=0.740 mathrm{~s}, a. lab tech measures the emf across the second coil, and the result is E=−3.70 V.mathscr{E}=-3.70 mathrm{~V} . What is the mutual inductance (in mHmathrm{mH} ) of the coils?



The post What must be the capacitance (in pFmathrm{pF}pF ) of the circuit so that the radio is tuned to a frequency of f=6.95MHzmathrm{f}=6.95 mathrm{MHz}f=6.95MHz ? appeared first on nursing assignment tutor.
The figure below shows a bar of mass m = 0.240 kg that can slide without friction on a pair of rails separated by a distance = 1.20 m and located on an inclined plane that makes an angle θ = 29.0° with respect to the ground. The resistance of the resistor is R = 2.20 Ω and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails?

